W.A.P To find out area of different shape using function overloading

#include<iostream.h>

#include<conio.h>

#include<math.h>

#define PI 3.14

            class shape {

            public:

                        float ar,ar2,ar3,s;

                        float area(int r) {

                          ar=PI*r*r;

                          return(ar);

                        }

                        float area(int l, int b) {

                                    ar2= l* b;

                                    return(ar2);

                        }

                        float area(int a, int b, int c) {

                                    s=(a+b+c)/2.0;

                                    ar3=sqrt(s*(s-a)*(s-b)*(s*c));

                                    return(ar3);

                        }

               void Display();

            };

             void shape :: Display() {

                        cout<<"\n\n\t\tArea of Circle...     "<<ar;

                        cout<<"\n\t\tArea of Rectangle....   "<<ar2;

                        cout<<"\n\t\tArea of Triangle.....   "<<ar3;

              }

              void main() {

                        clrscr();

                        shape s;

                        cout.precision(2);

                        s.area(5);

                        s.area(6,5);

                        s.area(5,3,4);

                        s.Display();

                        getch();

              }

              

OUTPUT:

Area of Circle...     78.5

Area of Rectangle....   30

Area of Triangle.....   20.78